Integrand size = 17, antiderivative size = 26 \[ \int (a+b \sec (c+d x)) \sin (c+d x) \, dx=-\frac {a \cos (c+d x)}{d}-\frac {b \log (\cos (c+d x))}{d} \]
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Time = 0.04 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.176, Rules used = {3957, 2800, 45} \[ \int (a+b \sec (c+d x)) \sin (c+d x) \, dx=-\frac {a \cos (c+d x)}{d}-\frac {b \log (\cos (c+d x))}{d} \]
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Rule 45
Rule 2800
Rule 3957
Rubi steps \begin{align*} \text {integral}& = -\int (-b-a \cos (c+d x)) \tan (c+d x) \, dx \\ & = \frac {\text {Subst}\left (\int \frac {-b+x}{x} \, dx,x,-a \cos (c+d x)\right )}{d} \\ & = \frac {\text {Subst}\left (\int \left (1-\frac {b}{x}\right ) \, dx,x,-a \cos (c+d x)\right )}{d} \\ & = -\frac {a \cos (c+d x)}{d}-\frac {b \log (\cos (c+d x))}{d} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.42 \[ \int (a+b \sec (c+d x)) \sin (c+d x) \, dx=-\frac {a \cos (c) \cos (d x)}{d}-\frac {b \log (\cos (c+d x))}{d}+\frac {a \sin (c) \sin (d x)}{d} \]
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Time = 0.78 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.00
method | result | size |
derivativedivides | \(\frac {-\frac {a}{\sec \left (d x +c \right )}+b \ln \left (\sec \left (d x +c \right )\right )}{d}\) | \(26\) |
default | \(\frac {-\frac {a}{\sec \left (d x +c \right )}+b \ln \left (\sec \left (d x +c \right )\right )}{d}\) | \(26\) |
parts | \(-\frac {a \cos \left (d x +c \right )}{d}+\frac {b \ln \left (\sec \left (d x +c \right )\right )}{d}\) | \(26\) |
risch | \(i b x +\frac {2 i b c}{d}-\frac {b \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}-\frac {a \cos \left (d x +c \right )}{d}\) | \(45\) |
parallelrisch | \(\frac {-a \cos \left (d x +c \right )-b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )-b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+b \ln \left (\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )+a}{d}\) | \(60\) |
norman | \(\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{d \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}+\frac {b \ln \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}{d}-\frac {b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{d}-\frac {b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{d}\) | \(89\) |
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Time = 0.28 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.96 \[ \int (a+b \sec (c+d x)) \sin (c+d x) \, dx=-\frac {a \cos \left (d x + c\right ) + b \log \left (-\cos \left (d x + c\right )\right )}{d} \]
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\[ \int (a+b \sec (c+d x)) \sin (c+d x) \, dx=\int \left (a + b \sec {\left (c + d x \right )}\right ) \sin {\left (c + d x \right )}\, dx \]
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Time = 0.19 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.88 \[ \int (a+b \sec (c+d x)) \sin (c+d x) \, dx=-\frac {a \cos \left (d x + c\right ) + b \log \left (\cos \left (d x + c\right )\right )}{d} \]
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Time = 0.30 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.23 \[ \int (a+b \sec (c+d x)) \sin (c+d x) \, dx=-\frac {a \cos \left (d x + c\right )}{d} - \frac {b \log \left (\frac {{\left | \cos \left (d x + c\right ) \right |}}{{\left | d \right |}}\right )}{d} \]
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Time = 0.04 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.88 \[ \int (a+b \sec (c+d x)) \sin (c+d x) \, dx=-\frac {a\,\cos \left (c+d\,x\right )+b\,\ln \left (\cos \left (c+d\,x\right )\right )}{d} \]
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